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A parallel beam of 500 keV photons is normally incident on a sheet of lead 8 mm thick. The rate of energy transmission is 4 x 10^4 MeV/s.

A parallel beam of 500 keV photons is normally incident on a sheet of lead 8 mm thick. The rate of energy transmission is 4 x 10^4 MeV/s.

a. what fraction of the incident photon energy is absorbed in the sheet?

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b. how many photons per second are incident on the sheet?

c. What fraction of the transmitted energy is due to uncollided photons?

I know the answer

A. 0.598

B. 1.99 x 195 s^-1

C. 0.580

Please tell me why!

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