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based on a linear model I have write an equation based on intercept and factors when y = 2. The model give me this formula y = 4.13143x + 1.01882. So…

based on a linear model I have write an equation based on intercept and factors when y = 2.4. The model give me this formula y = 4.13143x + 1.01882. So I would substitute 2.4 for y in this equation.

I then have to compare my result with the predict function in R. Which would be predict(name of my model, newdata = ?)

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based on a linear model I have write an equation based on intercept and factors when y = 2. The model give me this formula y = 4.13143x + 1.01882. So…
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